1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

[Differential Geometry] Simple relations between Killing vectors and curvature

  1. Jan 14, 2010 #1
    First of all, hello :)
    I'd like to request some aid concerning a problem that is really getting to me. I know it should be simple but I'm not getting the right results.

    1. The problem statement, all variables and given/known data
    Given that [tex]V^{\mu}[/tex] is a Killing vector, prove that:

    [tex]V^{\mu;\lambda}_{;\lambda} + R^{\mu}_{\lambda}V^{\lambda} = 0[/tex]

    And that:

    [tex]V_{\lambda;\alpha\beta} = R_{\lambda\beta\alpha\mu}V^{\mu}[/tex]

    Where ";" represents the covariant derivative with respect to the indexes that follow it.

    2. Relevant equations
    The Killing Equation and the ones pertaining to the Riemann tensor is my best guess. But the problem is stated merely as I did in the previous section. There might be some "trick" I'm unaware of that does not use them.

    3. The attempt at a solution
    The first equation I hit a standstill almost instantly as I don't know how to handle the "contravariant derivative". Can I even define a "contravariant connection"? And how do I maintain the proper degress of freedom in the terms? The covariant derivative of something must still be a "something" of the same nature. I'm confused here, I admit.

    On the second equation my work as proved more fruitful: I expand the two derivatives and obtain terms that resemble the Riemann tensor. My thought was to calculate the commutator to cut the extra terms and then use the fact that the cyclic sum of the last 3 indexes of the Riemann tensor vanishes together with the Killing equation to make the proof. But when I finish expanding the derivatives and subtract [tex]V_{\lambda;\beta\alpha}[/tex] from [tex]V_{\lambda;\alpha\beta}[/tex] I do not get a Riemann tensor multiplied by a Killing vector as I hoped I would, in fact, I get two terms on one component of the Killing vector, and two terms on another, different component of the Killing vector.

    I hope I was clear. I do all my calculations by hand, and don't know how I can show them here, or even if you'd want to see them (I am very thorough). I think I didn't break any of the forum rules but if there are any I'm not aware of, please tell me so I can redo the post accordingly.

    Thanks in advance for any help or insight. I know these should be easy, but I'm failing at a conceptual level, mainly I think I may be doing the second covariant derivative wrong, given the term from the first one :(

    P.S.: Rewrote formulas using tex tags. It's much clearer now :)

    Edit: removed the multitude of extra [1], [2] and [3] that appeared out of nowhere :S
    Edit 2: Misspelled Riemann :) Double "n", one "m", must remember >_<
     
    Last edited: Jan 14, 2010
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: [Differential Geometry] Simple relations between Killing vectors and curvature
Loading...