Applying Leibniz's Rule for Differentiating an Integral

rootX
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Homework Statement



\int_{x}^{2\,{x}^{2}+1}sin{t}^{2}dt

I need to take differential of that

Homework Equations



Fundamental theorem of calculus

The Attempt at a Solution



I know 't' is a dummy var, so I replace it with x,

and then
get
sin((2x^2+1)^2)-sin(x^2)
as answer. But I am not very sure about my answer.

Can anyone please check my solution?

Thanks.
 
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Look up Leibniz's Rule. After that it's just a plug and chug:

Edit: Leibniz Rule, not Theorem
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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