How Do You Differentiate f(x) = (71+x)/(1-x)?

AwesomeSN
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Homework Statement



Differentiate, f(x)=71+x/1-x

Homework Equations


The Attempt at a Solution



Working this out, hoping it's right as I was going along, my final answer is 71+x/1-x * (2ln7)/1-x
 
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Check your denominator...

Looks like you may have had a bit of a problem after you applied the chain rule. A great way to check your answers is to plug them in on www.wolframalpha.com. If you are incorrect, you can always ask us about the accuracy of your steps.
 
AwesomeSN said:

Homework Statement



Differentiate, f(x)=71+x/1-x

Homework Equations





The Attempt at a Solution



Working this out, hoping it's right as I was going along, my final answer is 71+x/1-x * (2ln7)/1-x

Please learn to typeset expressions properly; in particular, USE PARENTHESES. Your function is f(x) = 7(1+x)/(1-x). What you wrote actually means 71 + (x/1) -x = 7.

RGV
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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