Differentiating t/(1+t^2)^(1/2)

  • Thread starter Thread starter P.O.L.A.R
  • Start date Start date
  • Tags Tags
    Differentiating
P.O.L.A.R
Messages
22
Reaction score
0
d/dx[t/(1+t^2)^(1/2)]

The answer say 1/(1+t^2)^(3/2)

I can tget that for the life of me. Used product rule and I can't seem to simplify it I come up with

2/(1+t^2)^(3/2) Where does the 2 go? This is for a principal unit vector problem so a quick solution is all i need. thanks
 
Physics news on Phys.org
nevermind i got it forgot about the 2 on the bottom doh.
 
I'd say the answer was 0, but that's just my opinion..
 
arildno said:
I'd say the answer was 0, but that's just my opinion..

lol...
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top