Well, \sin \left ( x + \frac{\pi}{2} \right) = \cos x if that helps
I don't see why you'd want to change the second one though, taking the derivative is lineair so \left( {3\sin x - 2\cos x} \right)^\prime = 3\left( {\sin x} \right)^\prime - 2\left( {\cos x} \right)^\prime
#4
cscott
778
1
Damn, I guess I wasn't looking at them right. Thanks.
I'm reviewing Meirovitch's "Methods of Analytical Dynamics," and I don't understand the commutation of the derivative from r to dr:
$$
\mathbf{F} \cdot d\mathbf{r} = m \ddot{\mathbf{r}} \cdot d\mathbf{r} = m\mathbf{\dot{r}} \cdot d\mathbf{\dot{r}}
$$