Differentiation find dy/dx if y=x^y

Bachelier · 2010-06-20T08:26:22+00:00

I need to check my results on this integration find dy/dx if y=x^y I find: dy/dx= y^2/[x(1-yln(x))]

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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Thread 'Finding the nth roots of a complex number'

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