Differentiation of an exponential with operators (Peskin p.84)

gremezd
Messages
18
Reaction score
0
Does anyone know how to differentiate an exponential, which has an operator in its power? I found it quite a trouble in Peskin's QFT (page 84, formulas (4.17), (4.18)).
Here we have these two formulas of Peskin:

U\left( t,t_{0}\right)=e^{iH_{0}\left( t-t_{0}\right) }e^{-iH\left( t-t_{0}\right) };
i\frac{\partial}{\partial t}U\left( t,t_{0}\right)=e^{iH_{0}\left( t-t_{0}\right) }\left( H-H_{0}\right) e^{-iH\left( t-t_{0}\right) }.

I agree with this. However, if we write U\left( t,t_{0}\right) as U\left( t,t_{0}\right)=e^{i\left( H_{0}-H\right) \left( t-t_{0}\right) }, then

i\frac{\partial}{\partial t}U\left( t,t_{0}\right)=\left( H-H_{0}\right)e^{i\left( H_{0}-H\right) \left( t-t_{0}\right) }

and we cannot transport e^{iH_{0}\left( t-t_{0}\right) } to the left of \left( H-H_{0}\right) so easily to obtain Peskin's result, since, according to my calculations, \left[ H,H_{0}\right]\neq0. Do we have a rule, which explains where to put the operators from the exponential after differentiation, when we have several noncummuting operators in the power of exponential?
 
Physics news on Phys.org
gremezd said:
Does anyone know how to differentiate an exponential, which has an operator in its power? I found it quite a trouble in Peskin's QFT (page 84, formulas (4.17), (4.18)).
Here we have these two formulas of Peskin:

U\left( t,t_{0}\right)=e^{iH_{0}\left( t-t_{0}\right) }e^{-iH\left( t-t_{0}\right) };
i\frac{\partial}{\partial t}U\left( t,t_{0}\right)=e^{iH_{0}\left( t-t_{0}\right) }\left( H-H_{0}\right) e^{-iH\left( t-t_{0}\right) }.

I agree with this. However, if we write U\left( t,t_{0}\right) as U\left( t,t_{0}\right)=e^{i\left( H_{0}-H\right) \left( t-t_{0}\right) }, then
But you can't write this since H and H_0 don't commute. e^A e^B = e^{A+B} only when A and B commute. Otherwise you have to use the Campbell-Hausdorf formula.
i\frac{\partial}{\partial t}U\left( t,t_{0}\right)=\left( H-H_{0}\right)e^{i\left( H_{0}-H\right) \left( t-t_{0}\right) }

and we cannot transport e^{iH_{0}\left( t-t_{0}\right) } to the left of \left( H-H_{0}\right) so easily to obtain Peskin's result, since, according to my calculations, \left[ H,H_{0}\right]\neq0. Do we have a rule, which explains where to put the operators from the exponential after differentiation, when we have several noncummuting operators in the power of exponential?
You just differentiate as usual, making sure that you never pass an operator "through" another operator that does not commute with it.
 
Thanks a lot! This has been tormenting me for ages!
 
Thank you, nrqed, for pointing out my mistake. I appreciate it :)
 
gremezd said:
Thank you, nrqed, for pointing out my mistake. I appreciate it :)

:smile: You are very very welcome.

And thank you for posting your question since this apparently helped Wasia too!

Patrick
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

Similar threads

Back
Top