Differentiation of log function

b521
Messages
10
Reaction score
0

Homework Statement



Find an equation of the tangent line to the curve at the
given point.

y = ln(xe^(x²)) P=(1, 1)


The Attempt at a Solution



I know how to plug in the numbers into the Point-Slope formula once I find the derivative of the function, or slope, I'm just not sure how to derive this function.
 
Physics news on Phys.org
b521 said:

Homework Statement



Find an equation of the tangent line to the curve at the
given point.

y = ln(xe^(x²)) P=(1, 1)


The Attempt at a Solution



I know how to plug in the numbers into the Point-Slope formula once I find the derivative of the function, or slope, I'm just not sure how to derive this function.
First, use the properties of logarithms; namely ln(a*b) = ln a + ln b. Then, take the derivative. Presumably you know how to differentiate y = ln u, where u is a function of x.
 
Yes, thank you!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top