Differentiation Problem: Solving for d/dx in x^n(x-1)^n/n! * e^x

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SUMMARY

The discussion focuses on computing the derivative of the function \(\frac{x^{n}(x-1)^{n}}{n!} \times e^{x}\). The correct application of the product rule yields the derivative as \(\frac{x^{n-1}(x-1)^{n}e^{x}}{(n-1)!} + \frac{x^{n}(x-1)^{n-1}e^{x}}{(n-1)!} + \frac{x^{n}(x-1)^{n}e^{x}}{(n)!}\). The solution emphasizes the importance of correctly applying the product rule multiple times to achieve a simplified result.

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Homework Statement



Compute [tex]\frac{d}{dx}\left(\frac{x^{n}\left(x-1\right)^{n}}{n!} \times e^{x}\right)[/tex]

Homework Equations



[tex]\left(\frac{x^{n}\left(x-1\right)^{n}}{n!} \times e^{x}\right)[/tex]

The Attempt at a Solution



I got a solution of sorts applying the product rule and then applying the product rule again but it seemed awfully messy and i was wondering what the correct solution is and if there are steps taken to tidy all this up and give a nicer answer

Thanks
 
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Would you mind posting your answer? It may be ok, [tex]\frac {x^{n-1}(x-1)^{n}e^{x}}{(n-1)!} + \frac {x^{n}(x-1)^{n-1}e^{x}}{(n-1)!} + \frac {x^{n}(x-1)^{n}e^{x}}{(n)!}[/tex]
 

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