Difficulty solving the following question

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Discussion Overview

The discussion revolves around solving an integral involving an odd function, specifically the integral of \( t^3 \cos^3(10t) \). Participants explore various methods for evaluating the integral, including integration by parts and contour integration, while addressing the implications of the function's oddness on the integral's value.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants note that the integral is undefined but suggest that if defined, the Cauchy principal value could be a natural value to consider.
  • Others mention that since \( t^3 \) is an odd function and \( \cos(10t) \) is an even function, their product is odd, leading to the conclusion that the integral over symmetric limits should yield zero.
  • One participant suggests using integration by parts with symmetric limits to evaluate the integral, while acknowledging the complexity due to infinite limits.
  • Another participant raises the possibility of using contour integration as an alternative method.
  • There is a discussion about the implications of the limits of integration, with some asserting that if the integral is defined over symmetric limits, the result should be zero, while others argue that the integral is undefined if limits are not symmetric.
  • Participants express confusion over the mathematical proof of the function being odd and the nature of the integral's existence.

Areas of Agreement / Disagreement

Participants generally agree that the function is odd and that the integral over symmetric limits should yield zero. However, there is disagreement regarding the implications of undefined integrals and the conditions under which the Cauchy principal value applies. The discussion remains unresolved regarding the mathematical proof of the function's oddness and the integral's existence.

Contextual Notes

Limitations include the dependence on definitions of odd functions and improper integrals, as well as unresolved mathematical steps regarding the evaluation of the integral.

skyflyer54
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Hi, having difficulty solving the following question.. Any1 can help me and guide me through solving it ?? or is there any good website or reference to recommand ?? Thankz a lot..
 

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The integral is undefined. However, if you were to define it, there's a particular value that seems pretty natural. To help you guess what that might be, notice that [itex]x(t)[/itex] is an odd function:

[tex]x(-t) = (-t)^3\cos (-10t)^3 = -t^3\cos (10t)^3 = -x(t).[/tex]

Does that help? :smile:

(the "natural" value for the integral that I'm speaking of is the Cauchy principal value)
 
Oh.. I only know the shortcut method but don't know whether u are referring to it or not...

I only know that 't' is odd function and cos(10t) is even function.. so multiply odd with even will give me odd function...

I'm confused is the part on how to solve it mathematically said integration by parts.. haha ...
 
skyflyer54 said:
Oh.. I only know the shortcut method but don't know whether u are referring to it or not...

I only know that 't' is odd function and cos(10t) is even function.. so multiply odd with even will give me odd function...

I'm confused is the part on how to solve it mathematically said integration by parts.. haha ...

To integrate that function integration by parts would work, but would probably be extremely messy, the problem you will run into is evaluating the integral since both limits will be infinite and the improper integral will be undefined as Data said above.
 
If you wanted to use integrate by parts you could probably set the upper and lower limits of integration to some constant [itex]\pm a[/itex]. This symmetric choice of limits will allow you to evaluate the integral by parts, by utilising the symmerty properties of the the now-integrated function to determine what cancellations occur etc. Then in the final step take the limit of [itex]|a|\to\infty[/itex].
 
what about contour integration?
 
jpr0 said:
If you wanted to use integrate by parts you could probably set the upper and lower limits of integration to some constant [itex]\pm a[/itex]. This symmetric choice of limits will allow you to evaluate the integral by parts, by utilising the symmerty properties of the the now-integrated function to determine what cancellations occur etc. Then in the final step take the limit of [itex]|a|\to\infty[/itex].

That is precisely taking the Cauchy principal value. It is trivial to see what the result will be, because x is odd.
 
Okie.. Thank every1 for the guide and comment given.
 
shouldn't the result be zero since the function is odd?
 
  • #10
Yes, for any A,
[tex]\int_{-A}^{A} t^3 cos^3(10t)dt= 0[/tex]
so the limit as A->infinity, the "Cauchy Principal Value" would be 0. That's what everyone has been saying.

Data said that integral is undefined because the actual improper integral must be
[tex]\int_{-A}^B x^3 cos^3(10t)dt[/tex]
with A and B going to infinity independently. That is undefined.
 
  • #11
tat true.. if the limit is from A to -A or even from Infinity to -Infinity, the result will be zero. If it is undefined, say like limit from A to B den the answer should not be zero. right ?

This question in the first place was just to solve it to be odd function using mathematical approach. kekez..

Did I said anything wrong ? If yes, pls correct mi. thankz.. heez.
 
  • #12
skyflyer54 said:
tat true.. if the limit is from A to -A or even from Infinity to -Infinity, the result will be zero. If it is undefined, say like limit from A to B den the answer should not be zero. right ?

This question in the first place was just to solve it to be odd function using mathematical approach. kekez..

Did I said anything wrong ? If yes, pls correct mi. thankz.. heez.
Yes, the "even from infinity to -infinity" is wrong. As I said before
[tex]\int_{-\inty}^\infty f(x) dx= \lim_{A\rightarrow -\infty}\lim_{B\rightarrow \infty} \int_A^B f(x)dx[/tex]

Certainly, if an integral is "undefined", then it is not 0! The original question was to find the value of that integral if it existed. I don't know what you mean by "solve it to be odd function".
 
  • #13
From observation, we already know that the function is an odd function, but What i mean is solve and proof it that the equation is an odd function. what i mean is solve and proof it mathematically if possible.
 
  • #14
skyflyer54 said:
From observation, we already know that the function is an odd function, but What i mean is solve and proof it that the equation is an odd function. what i mean is solve and proof it mathematically if possible.
I have absolutely no idea what you mean. You say "What i mean is solve and proof it that the equation is an odd function" but you had just said "we already know that the function is an odd function". Prove what mathematically?
That the integral given doesn't exist?

That the Cauchy Principal Value is 0?
 
  • #15
HallsofIvy said:
I have absolutely no idea what you mean. You say "What i mean is solve and proof it that the equation is an odd function" but you had just said "we already know that the function is an odd function". Prove what mathematically?
That the integral given doesn't exist?

That the Cauchy Principal Value is 0?

ok.. thank.. maybe i should read up cachy principal again..
 

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