Dimensional analysis universal gravitation

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To determine the SI units of the gravitational constant G in Newton's law of universal gravitation, the equation F = GMm/r^2 is rearranged to G = Fr^2/(Mm). The units of force (F) are expressed as newtons (N), which equals kg·m/s². By substituting the units into the equation for G, it simplifies to m³/(kg·s²). The final result confirms that the units of G are indeed m³/kg·s², aligning with the answer provided in the textbook. The discussion also touches on using LaTeX for mathematical formatting.
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Firstly, I admit that my math skills are fairly rusty. I also admit that this is a homework problem. It is not to be turned in for a grade however.
The problem is to determine the SI units of G in the following equation:

F = GMm/r^2

(where F is force (mass * acceleration), M and m are the masses of two objects, and r is a distance)
which is, of course, Newton's law of universal gravitation.
I would be greatly appreciative if someone could walk through the steps needed to make this determination.
 
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Work it out for G:

F = G\frac{{m_1 \cdot m_2 }}{{r^2 }} \Leftrightarrow G = \frac{{F \cdot r^2 }}{{m_1 \cdot m_2 }}

I suppose you now the units of the RHS, LHS has to be equal :smile:
 
Thanks for that. The answer in the back of the book is quite different, however. It is given as m^3/kg*s^2. I'm working on it. Do you think you could go into more detail? Again, my skills are a little rusty. Also, how'd you get the math font into your message?
 
I just worked it out for G. Now you have to replace the right hand side by all their units and simplify to find the unit of G.
 
1N = kg \frac {m}{s^2}
for font (LaTex) read first threads in General Physics forum :smile:

edit: where 1N is unit of force.
 
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