Dimensional Analysis with volume?

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In dimensional analysis, units can be manipulated similarly whether they are cubed or not. For instance, to convert cubic meters to cubic centimeters, the conversion starts with the relationship that 1 meter equals 100 centimeters. Therefore, when converting 1 m³, it can be expressed as (1 m)³, which equals (100 cm)³. This leads to the calculation that 1 m³ is equal to 100³ cm³, resulting in 1 m³ equating to 1,000,000 cm³ (or 10^6 cm³). The essential principle is that unit conversions maintain equality, allowing for the distribution of exponents across both the numerical value and the unit itself.
Titandwedebil
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Can you work units cubed the same way you can work units that aren't cubed in dimensional analysis?

Like...does 1m3 equal 250cm3 like it would if they weren't cubed?
 
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I'm not sure where you're getting 1 m^3 = 250 cm^3, but here's how things work:

If you have 1 m^3 and you want to convert to cm cubed, you can use the fact that 1 m = 100 cm. Since 1 m^3 is really just (1 m)^3, I can write (1 m)^3 = (100 cm)^3. The power of 3 now has to distribute over both the unit and the number, so we get that

1 m^3 = 100^3 cm^3 = 10^6 cm^3.

The key point to take away is that a relation between units like 1 m = 100 cm is an equality, so you can always replace a unit with one of these equalities, and then distribute the powers over both the unit and the number, as done in this example here.
 
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