Dirac-Delta Functions and Double Integrals

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SUMMARY

The discussion focuses on the mathematical properties of Dirac-delta functions, specifically demonstrating that \(2C \cdot \delta(x-ct) \cdot \delta(x+ct) = \delta(x) \cdot \delta(t)\). Participants explore the implications of taking derivatives and integrating these functions, emphasizing the need to understand the definition of the Dirac delta function. The conversation also touches on calculating double integrals involving Dirac-delta functions after parameter transformations.

PREREQUISITES
  • Understanding of Dirac-delta function properties
  • Knowledge of calculus, specifically integration and differentiation
  • Familiarity with parameter transformations in multivariable calculus
  • Experience with double integrals involving delta functions
NEXT STEPS
  • Study the properties of the Dirac delta function in detail
  • Learn how to perform parameter transformations in double integrals
  • Explore examples of integrating functions involving Dirac-delta functions
  • Investigate the implications of derivatives of Dirac-delta functions in calculus
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Mathematicians, physics students, and anyone involved in advanced calculus or theoretical physics who seeks to deepen their understanding of Dirac-delta functions and their applications in integrals.

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Homework Statement



show that [itex]\delta[/itex](x-ct)[itex]\delta[/itex](x+ct) = [itex]\delta[/itex](x)[itex]\delta[/itex](t)

P.S. sorry I mean't:

show that 2C*[itex]\delta[/itex](x-ct)[itex]\delta[/itex](x+ct) = [itex]\delta[/itex](x)[itex]\delta[/itex](t)

Homework Equations



calculus and Dirac-delta properties

The Attempt at a Solution



[tex]d/dx \int_{-\infty}^x\delta(x-ct)\delta(x+ct) = \delta(x)\delta(t) dx[/tex]

P.S. sorry I mean't:

[tex]2C*d/dx \int_{-\infty}^x\delta(x-ct)\delta(x+ct) = ...[/tex]

there are a couple of really weird steps that somebody else used after the above
 
Last edited:
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zheng89120 said:

Homework Statement



show that [itex]\delta[/itex](x-ct)[itex]\delta[/itex](x+ct) = [itex]\delta[/itex](x)[itex]\delta[/itex](t)

Homework Equations



calculus and Dirac-delta properties

The Attempt at a Solution



[tex]d/dx \int_{-\infty}^x\delta(x-ct)\delta(x+ct) = \delta(x)\delta(t) dx[/tex]

there are a couple of really weird steps that somebody else used after the above

Why are you taking the derivative? How is the Dirac delta function defined?
 
Hi zheng89120! :smile:

Do you know how to calculate for any generic function f(u,v):
[tex]\iint f(x-ct, x+ct) 2c \delta(x-ct) \delta(x+ct) dxdt[/tex]

And do you also know how to calculate this double integral after a parameter transformation to (u, v), where u=x-ct and v=x+ct?
 

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