Dirac Principle Value Identity applied to Propagators

maverick280857
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Hi,

How is

\frac{1}{\displaystyle{\not}{P}-m+i\epsilon}-\frac{1}{\displaystyle{\not}{P}-m-i\epsilon} = \frac{2\pi}{i}(\displaystyle{\not}{P}+m)\delta(P^2-m^2)

? This is equation (4-91) of Itzykson and Zuber (page 189). I know that

\frac{1}{x\mp i\epsilon} = \mathcal{P}\left(\frac{1}{x}\right) \pm i\pi\delta(x)

But this doesn't seem to give the right hand side of the first equation above. What am I missing?

Thanks in advance!
 
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maverick280857 said:
Hi,

How is

\frac{1}{\displaystyle{\not}{P}-m+i\epsilon}-\frac{1}{\displaystyle{\not}{P}-m-i\epsilon} = \frac{2\pi}{i}(\displaystyle{\not}{P}+m)\delta(P^2-m^2)

? This is equation (4-91) of Itzykson and Zuber (page 189). I know that

\frac{1}{x\mp i\epsilon} = \mathcal{P}\left(\frac{1}{x}\right) \pm i\pi\delta(x)

But this doesn't seem to give the right hand side of the first equation above. What am I missing?

Thanks in advance!

How does the (\displaystyle{\not}{P} + m) appear?
 
It's because P/ - m is a matrix, and so first you have to write 1/(P/ - m) as (P/ + m)/(P2 - m2).

So in detail,

1/(P/ - m + iε) - 1/(P/ - m + iε) = (P/ + m)[1/(P2 - m2 + iε) - 1/(P2 - m2 - iε)]
= (P/ + m)[-iπ δ(P2 - m2) -iπ δ(P2 - m2)] = (P/ + m)(-2iπ δ(P2 - m2))
 
Bill_K said:
It's because P/ - m is a matrix, and so first you have to write 1/(P/ - m) as (P/ + m)/(P2 - m2).

So in detail,

1/(P/ - m + iε) - 1/(P/ - m + iε) = (P/ + m)[1/(P2 - m2 + iε) - 1/(P2 - m2 - iε)]
= (P/ + m)[-iπ δ(P2 - m2) -iπ δ(P2 - m2)] = (P/ + m)(-2iπ δ(P2 - m2))

Thanks BillK, that cleared it up!
 
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