Dirac's Postulations: A Scalar Function or Four-Dimensional Vector?

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Hello Friends,

About Dirac's postulation about non conmutative operators and the scalar function with 4 elements, some questions:

why this function is a scalar function? Couldn't it be a four-dimensional vector? Why?

Best Reggards.
 
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Which scalar function with 4 elements are you talking about?Please make a specific reference.I have no idea what you're referring to.

Daniel.
 
HIlbert

Hello Dextercioby and forum,

How are u? I'm agreed to re-read u!

The question is this:

In Dirac's i \frac{\partial \Psi} {\partial t} =[\alfa (p-eA) + \beta m + e \O ] \Psi or Schrödinger's i\frac{\partial\Psi}{\partial t} = \frac{\hbar^{2}}{2m}\frac{\partial^{2}\Psi}{\partial x^{2}} + V\Psi, the wave function is a Hilbert Space wave, I think. Are they vectors or scalars?
The Hilbert Space is a vectorial, or scalar space?¿?

My best reggards.
 
1.A Hilbert space is a complete VECTOR SPACE with scalar product over the field of complex numbers...

2.Schroedinger's wave-function
\Psi (\vec{r},t)
is a vector from the Hilbert space \mathbb{L}^{2}(\mathbb{R}^{3})\otimes \mathbb{R}.

3.Dirac's field
\Psi^{\alpha} (x^{\mu})
is essentially a 4-spinor (Dirac spinor,if u prefer) and is an element of the vector space of the representation (\frac{1}{2},0) \oplus (0,\frac{1}{2}) of the restricted Lorentz group.The algebric structure determined by these spinors is actually a Grassmann algebra with involution over the vector space mentioned earlier...

Once you quantize Dirac's field,the classical spinors become operators and that's another (quite complicated ) story...

Daniel.
 
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thanks

Thanks you another time! :wink:
 
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