kryptyk
- 41
- 0
I'm still new to much of this stuff, so I do not claim to be an expert. But I thought I'd still comment. I'm trying to better understand the geometric calculus of David Hestenes:
http://modelingnts.la.asu.edu/
A fairly common form for the Fundamental Theorem of Calculus is:
\int_S d\omega = \oint_{\partial S} \omega
Typically only scalar \omega are considered. However, it is also possible to consider multivector-valued \omega in which case d\omega is a directed measure rather than a scalar.
Any smooth manifold will have a pseudoscalar field at every point x which we denote by I(x). For an n-dimensional manifold, this will be an n-blade which identifies the tangent space at the point x. I talked a bit about blades in this thread:
https://www.physicsforums.com/showthread.php?t=114604
For flat manifolds, I is constant. In fact, one could use this as the defining condition for flatness. So then:
d\omega = \mid d\omega\mid I
There seem to be some advantages to this approach. Any ideas?
http://modelingnts.la.asu.edu/
A fairly common form for the Fundamental Theorem of Calculus is:
\int_S d\omega = \oint_{\partial S} \omega
Typically only scalar \omega are considered. However, it is also possible to consider multivector-valued \omega in which case d\omega is a directed measure rather than a scalar.
Any smooth manifold will have a pseudoscalar field at every point x which we denote by I(x). For an n-dimensional manifold, this will be an n-blade which identifies the tangent space at the point x. I talked a bit about blades in this thread:
https://www.physicsforums.com/showthread.php?t=114604
For flat manifolds, I is constant. In fact, one could use this as the defining condition for flatness. So then:
d\omega = \mid d\omega\mid I
There seem to be some advantages to this approach. Any ideas?
Last edited: