Hi guys, sorry to ask such a basic question, but I'm studying for the MCAT and need to get my fundamentals down! Anyway, my question is this: Consider an object which has been thrown straight up into the air. It will rise, then at the very top of its ascent, it changes direction and comes back down. Now, I'm pretty sure that at the moment when the object reaches its maximum height, the velocity becomes zero, although there must still be an acceleration (due to gravity), or else the object wouldn't fall back down again. So, on a velocity-time graph, we would see a point where the velocity drops to zero, corresponding to the moment the object reaches its maximum height, right? Let's call this point q. But I am confused, because, since velocity is a vector, it has a direction. In this case, the direction would be up as we approach q from the left, and down as we approach q from the right. So what would the direction of the velocity vector be, when we are actually at that point? I am tempted to say that, since the magnitude of the velocity vector is 0m/s, the object isn't actually moving in *any* direction. But if that is the case, then *when* does the direction of the object officially change from up to down? Again, sorry to ask such a newbie question. If someone could elaborate on the behavior of the object at this point I would seriously appreciate it!