Discover the Answer to e^(xln(y)) with Quick and Easy Calculations | x = -1.18

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What does e^(xln(y)) equal?

EDIT: x being a number, -1.18
 
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e^(xln(y)) = (e^ln(y))^x = y^x

*@hgfalling corrected :)
 
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Wait, what?

e^{x \ln y} = (e^{\ln y})^x = y^x
 
ok, thankyou but it actually didn't help, my problem is below:

maCln(t/600)+mbCvln(t/500)=0

Where ma, C, mb and Cv are known, how do I work out t?
 
Make both sides a power of e. But first, turn it into one logarithm.

a log(x) + b log(y) = log(x^a y^b)
 
Doing that gives me:

(t/600)^(26x10^3)x(t/500)^(21.99x10^3)=0

Which doesn't seem solvable to me!

Any ideas?
 
eddysd said:
Doing that gives me:

(t/600)^(26x10^3)x(t/500)^(21.99x10^3)=0

Which doesn't seem solvable to me!

Any ideas?

Try another log rule. Like ln(t/600)=ln(t)-ln(600).
 
Thanks for all the help, think I've got it sorted now!
 
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