MathNerd
I know that this isn’t very practical but I discovered the following curious inequality when I was playing around with d(n) where d(n) gives the number of divisors of n \ \epsilon \ N. If n has p prime factors (doesn’t have to be distinct prime factors e.g. 12 = 2^2 \ 3 has got three prime factors (2,2,3)), Then
p + 1 \leq d(n) \leq \sum_{k=0}^{p} _{p} C_{k}
I don’t know if this has been previously discovered but giving its simplicity it wouldn’t surprise me if it has.
p + 1 \leq d(n) \leq \sum_{k=0}^{p} _{p} C_{k}
I don’t know if this has been previously discovered but giving its simplicity it wouldn’t surprise me if it has.
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