Discrete Math Help: Proving Injectivity of f & g

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Homework Statement



f: B => C and g: A => B

1. If f of g is injective, then f is injective.

2. If f of g is injective, then g is injective.

Homework Equations



The Attempt at a Solution

I know that 1 is true and 2 is false because I found those as properties, but I am not exactly sure why, and I do not know how to show a proof.

Any help please?
 
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If f of g is injective then every x,y in A such that f(g(x)) = f(g(y)) implies that x=y.

I suggest from here to suppose that f or g is not injective and come up with a contradiction. Ie: suppose f is injective and g is not injective, suppose f is not injective and g is injective, suppose f and g are not injective. Work it out from here.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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