What is a discrete-space derivative?

  • Thread starter Thread starter WhiteRae
  • Start date Start date
  • Tags Tags
    Derivative
WhiteRae
Messages
13
Reaction score
0
I was looking up how to find the derivative of a factorial and found this thread:
https://www.physicsforums.com/showthread.php?t=1328

What is a discrete-space derivative? I tried looking it up, but had no luck. If someone could explain it in a way someone in calc 2 could understand that would be great, or at least point me in the direction of more information.
 
Physics news on Phys.org
A discrete space is a space where all subsets are open. I have never heard of a discrete space derivative, however.

Have you heard of the gamma function? http://en.wikipedia.org/wiki/Gamma_function
Take a look at how it relates to the factorial function. It does take a lot of work to understand if you're only at the first year level in math.
 
I was looking at the Gamma Function. I understood it a little bit, but in general it was way over my head.
 
WhiteRae said:
What is a discrete-space derivative? I tried looking it up, but had no luck. If someone could explain it in a way someone in calc 2 could understand that would be great, or at least point me in the direction of more information.

The general idea is that the more familiar continuous space derivative,

\frac{df}{dx}=\lim_{\Delta x\to 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}

Can be generalized in cases where the smallest possible difference between two different values of a discrete variable x is a constant (in other words, all elements of the set are equally spaced) \delta x according to the equation

\frac{df}{dx}=\frac{f(x+\delta x)-f(x)}{\delta x}

(For a continuous space, \delta x is infinitesimally small)

If x is only allowed to be a natural number, then the smallest diffence between two different values of x is 1, and so

\frac{df}{dx}=f(x+1)-f(x)

Whether or not this is really the type of derivative you are interested in depends on the context of your problem.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top