Disintegration Energy of Beta Plus Decay

AI Thread Summary
The discussion focuses on calculating the disintegration energy for the beta plus decay of the radionuclide 11C. The correct formula for disintegration energy is established as Q = (mC - mB - 2me) c2, where mC and mB represent the atomic masses of carbon and boron, respectively, and me is the mass of an electron. Participants clarify that the masses used in the calculation are atomic rather than nuclear, leading to the inclusion of the electron mass twice in the equation. The final consensus confirms the accuracy of the derived formula for disintegration energy. Understanding the distinction between atomic and nuclear masses is crucial for this calculation.
xoxomae
Messages
23
Reaction score
1

Homework Statement


The radionuclide 11C decays according to
116C → 115B + e+ + v
Show that the disintegration energy is given by
Q = (mC - mB - 2me) c2

Homework Equations


Q = (mi - mf) c2

The Attempt at a Solution


[/B]
Q= (mC - mB - me) c2

Im probably missing something obvious but I can't see where the 2me comes from.
 
Physics news on Phys.org
The key is to remember that the given masses mC and mB are atomic masses, not nuclear masses.
 
But that leads me to
Q = ((mC+6mE) - (mB + 5mE + mE))c2

Which gives me
Q= (mC + mB)c2
 
To get the nuclear mass of the carbon, should you add 6 electrons to the atomic mass?
 
Ah i think I understand

Q = ((mC- 6mE) - (mB - 5mE + mE))c2

Q = (mC - mB - 2me) c2

Is this right?
 
Looks right. Good.
 
Thank You :)
 
Back
Top