Disintegration of a falling drop of liquid

AI Thread Summary
The maximum diameter of a falling liquid drop that will not disintegrate in a gas is influenced by several variables, including interfacial energy and viscosity. Drop breakup occurs primarily due to the forces acting on the drop as it falls, with larger drops being more susceptible to fragmentation. The discussion highlights the importance of understanding the balance between these forces to predict drop behavior. Additionally, the timescale of disintegration is closely related to the viscosity of the liquid. Overall, the dynamics of drop disintegration are complex and depend on multiple physical properties.
ca2n
Messages
10
Reaction score
0
What are the variables that determine the maximum diameter of a drop of liquid that will not disintegrate while falling through a gas (e.g. raindrop falling in air)?
 
Physics news on Phys.org
If you mean "fragment" by disintegrate (as opposed to evaporate), then drop breakup is driven by interfacial energy, at a timescale driven by the viscosity.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top