A uniform disk of mass Mdisk = 4.4 kg and radius R = 0.28 m has a small block of mass mblock = 2.4 kg on its rim. It rotates about an axis a distance d = 0.18 m from its center intersecting the disk along the radius on which the block is situated.(adsbygoogle = window.adsbygoogle || []).push({});

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a) What is the moment of inertia of the block about the rotation axis?

Iblock = kg*m2

2*0.18*0.18 NO

HELP: Remember: the block is on the rim of the disk.

HELP: The block is considered a point-mass.

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b) What is the moment of inertia of the disk about the rotation axis?

Idisk = kg*m2 *

4.4*0.28^2/2+4.4*0.18^2 OK

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c) When the system is rotating about the axis with an angular velocity of 5 rad/s, what is its energy?

KErot = J

(2.4*0.18^2+4.4*0.28^2/2+4.4*0.18^2)*5.0^2/2 NO

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d) If while the system is rotating with angular velocity 5 rad/s it has an angular acceleration of 8.4 rad/s2, what is the magnitude of the acceleration of the block?

|ablock| = m/s2

((5^2*0.18)^2+(8.4*0.18)^2)^(1/2) NO

Somebody please help!!!!!

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# Homework Help: Disk and Block

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