Dispersion relation (particle in a box)

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In solid state physics, the energy of a particle in a one-dimensional box is expressed as E = n^2 (pi)^2 (h_bar)^2 / 2mL^2, which can also be rewritten as E = (h_bar)^2 k^2 / 2m. This formulation suggests a relationship between energy eigenvalues E and the wave vector k, which is interpreted as momentum in certain contexts. While momentum itself is not an eigenstate, the square of momentum, p^2, is an eigenstate, allowing for k^2 to be viewed as its eigenvalue. In the large volume limit, the energy spectrum becomes independent of boundary conditions, supporting the interpretation of k as momentum under periodic boundary conditions. Understanding these relationships is crucial for grasping the fundamentals of solid state physics.
HAMJOOP
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I am learning some basic solid state physics idea, like density of state ...etc.

For particle in a 1D box,

E = n^2 (pi)^2 (h_bar)^2 / 2mL^2

But why it is written as
E = (h_bar)^2 k^2 /2m

does it means that energy eigenvalue E is related to momentum k ?
I guess it is not because momentum is not eigenstate.

But what is this expression talking about anyway ? what is the physical meaning of this k ?
 
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While p isn't an eigenstate, p^2 is. So take k^2 as eigenvalue of p^2. In solid state physics the point is that the energy spectrum in the large volume limit becomes independent of the boundary conditions. So you could also assume periodic boundary conditions and interpret k as momentum.
 

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