Vandetah
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Homework Statement
A small body is undergoing simple harmonic motion on a frictionless horizontal surface with an amplitude of 0.13m. At a point 0.05 m from equilibrium the velocity is 0.24 m/s. a.) what is the period?
What is the displacement and acceleration when the velocity is ±0.10 m/s
Homework Equations
T = 2∏ √\frac{l}{g}
Displacement = \frac{a}{\frac{-4∏^{2}}{T^{2}}}
acceleration = \frac{v^{2}}{A}
The Attempt at a Solution
T = 2∏ √\frac{0.05m}{g}
T = 0.45 S
Displacement = \frac{0.08 m/s^{2}}{\frac{-4∏^{2}}{0.45 S^{2}}}
= -4.10 x 10^{-4} m
acceleration = \frac{0.10m/s^{2}}{0.13m}
= 0.08 m/s^{2}
how is it?