Displacement of deflected puck on ice

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The discussion focuses on calculating the total displacement of a puck that travels 20.0 m at 5 degrees east of north and then 30.0 m at 35 degrees north of west. Participants express confusion about the correct representation of the vectors and the direction of the arrowheads in their diagrams. Suggestions include using the law of cosines for calculations, but a simpler vector addition method is preferred by some. There is a request for visual aids to clarify the situation, with emphasis on properly aligning the second displacement vector with the end of the first. Ultimately, the goal is to accurately determine the puck's final position relative to its starting point.
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Homework Statement


a puck on the ice travels 20.0 m [5.0 degrees E of N], gets deflected, and travels 30.0 m [35.0° N of W]. Determine where the puck will end up with respect to its starting point, e.g., the puck's total displacement

Homework Equations


c^2=a^2+b^2-2abcosC

The Attempt at a Solution


I made one going north east and labeled it 5 degrees, and one going north west but i don't know what direction the arrowhead should go in...
 
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I'm not sure I understand what you're confused about in your solution. Could you attach an image of your drawing of the situation?

You could use the law of cos but I personally would do it in a simpler way.
 
Brian T said:
I'm not sure I understand what you're confused about in your solution. Could you attach an image of your drawing of the situation?
I cannot unfortunately, can you attach what you would think is the diagram for this?
 
hafsa786786786 said:
I cannot unfortunately, can you attach what you would think is the diagram for this?

You should be able to scan a sketch and upload it. Have you tried?
 
Moderator note: Please note that the thread title has been changed in order to make it more descriptive of the problem statement - gneill
 
berkeman said:
You should be able to scan a sketch and upload it. Have you tried?
berkeman said:
You should be able to scan a sketch and upload it. Have you tried?
 

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Well other than being sideways, that helps. The 2nd displacement should start at the end of the first displacement. So using arrows to represent the displacement vectors, keep the first one you've drawn from the origin with the arrow pointing up and right. Then put the start of the 2nd arrow at the upper tip of the first arrow, and draw it up and left. Basically you just have to redraw your 2nd displacement vector...
 
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