1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Displacement of wood block originally attached to spring

  1. Oct 21, 2011 #1
    1. The problem statement, all variables and given/known data
    A 180-g wood block is firmly attached to a light horizontal spring, Fig. 6-26. The block can slide along a table where the coefficient of friction is 0.30. A force of 20 N compresses the string 18 cm. If the spring is released from this position, how far beyond its equilibrium will it stretch on its first string?

    2. Relevant equations
    Elastic PE = 1/2*kx^2

    3. The attempt at a solution
    We have 20 = 0.18k where k is in N/m. So k= 1000/9. Then this means the elastic potential energy is 1/2*20*(0.18)^2=1.8 J. Work due to friction is F_fr*displacement=0.3*0.18*9.8*displacement=.5292*displacement=1.8, and solving yields ≈3.4 m. Not correct, apparently.

    Can anyone show me where I went wrong?
  2. jcsd
  3. Oct 22, 2011 #2

    Doc Al

    User Avatar

    Staff: Mentor

    You set all of the initial elastic potential energy equal to the work done by friction. But since it's stretching past equilibrium, the final position (of momentary rest) will also have some elastic potential energy.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Displacement of wood block originally attached to spring