Displacement reaction at solubulity limit. Does it stop or precipitate

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In a single displacement reaction, if the displacing metal reaches its solubility limit before fully displacing the other metal, the reaction will continue until all available ions are reacted. In the example of lead displacing silver from silver nitrate, lead nitrate (Pb(NO3)2) can precipitate out once its solubility limit is reached. This means that while the displacement may slow down due to the saturation of the solution, the reaction does not stop entirely. Instead, excess lead nitrate will form as a precipitate, allowing the reaction to proceed until all available silver ions are displaced.
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I'm wondering what happens in a single displacement reaction if the displacing metal (the one that's going into the solution) reaches it's solubility limit before the other metal in the solution is fully displaced.

Say for example you had a strong silver nitrate solution, and you placed enough solid lead in it to potentially displace all of the silver.

Pb + 2AgNO3 -> 2Ag + Pb(NO3)2

Since AgNO3 has approx four times more solubility than Pb(NO3)2, it is possible that the Pb(NO3)2 would reach it's solubility limit before all of the Ag is displaced. So when this happens does the displacement just stop (or drastically slow), or does the reaction continue, with the excess Pb(NO3)2 precipitating out?
 
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Reaction continues, precipitating lead nitrate.
 
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