- #1
madah12
- 326
- 1
i just studied S.H.M and i am wondering is the displacement equals the amplitude or zero after the periodic time?
because when i thought it equals zero at first because the periodic time is time required for the object to make acomplete oscillation and return to it's starting point right?
but when i put the law T= [tex]2\pi\ \sqrt{m/k}[/tex]
T= [tex]2\pi\ *\sqrt{m/f/x}[/tex]
T= [tex]2\pi\ *\sqrt{m/mg/x}[/tex]
T=[tex]2\pi\ *\sqrt{x/g[/tex] (and unless the periodic time of every S.H.M is 0 this can't be right )and no this isn't home but i asked the tried to ask the teacher and he didnt have time to listen.
And this is like my first lesson in S.H.M so i don't understand it that much.
maybe i didnt understand the periodic time right or something like that
also since y = A Sin (wt)
y = Asin ([tex]2\pi/T\[/tex]*T
y = Asin([tex]2\pi[/tex]=0
because when i thought it equals zero at first because the periodic time is time required for the object to make acomplete oscillation and return to it's starting point right?
but when i put the law T= [tex]2\pi\ \sqrt{m/k}[/tex]
T= [tex]2\pi\ *\sqrt{m/f/x}[/tex]
T= [tex]2\pi\ *\sqrt{m/mg/x}[/tex]
T=[tex]2\pi\ *\sqrt{x/g[/tex] (and unless the periodic time of every S.H.M is 0 this can't be right )and no this isn't home but i asked the tried to ask the teacher and he didnt have time to listen.
And this is like my first lesson in S.H.M so i don't understand it that much.
maybe i didnt understand the periodic time right or something like that
also since y = A Sin (wt)
y = Asin ([tex]2\pi/T\[/tex]*T
y = Asin([tex]2\pi[/tex]=0
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