Distance in time at acceleration

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The discussion centers on finding the time it takes for an object to travel a distance under constant acceleration, starting from an initial velocity. The relevant formula is derived from the equation d = d₀ + v₀t + (1/2)at², which requires rearranging to incorporate initial velocity. A specific example involves a rocket traveling at 1000 m/s that accelerates at 100 m/s² towards the sun, with a distance of 1000 km to cover. The proposed formula for time is t = d / ((sqrt(v₀² + 2ad) + v₀) / 2). The conversation highlights the challenge of rearranging formulas for those with lower math skills.
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what is the formula to find the time it takes for an object to travel a distance at a certain acceleration from a certain initial velocity? I think I've figured out it without taking into account the initial v which would be t = squareroot( (d * 2) / a), i think... but I'm not sure how to fit the initial velocity in there.
 
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Can you show some work?
 
dirty_d said:
what is the formula to find the time it takes for an object to travel a distance at a certain acceleration from a certain initial velocity? I think I've figured out it without taking into account the initial v which would be t = squareroot( (d * 2) / a), i think... but I'm not sure how to fit the initial velocity in there.

Start off with the equation d = d_{0}+v_{0}t+\frac{1}{2}at^2. The equation you got would be valid for d0 = v0 = 0.
 
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radou i have no idea how to rearrange that formula, cyrusabdollahi, an example would be if a rocket is in space with the engine off traveling at 1000 m/s towards the sun and then turns the engine on and starts accelerating at 100 m/s/s in the same direction how long would it take to travel 1000 km towards the sun from when it starts accelerating.
 
What is your level of math?
 
level = low
 
anybody...
 
this works i don't know if it can be simplified any,

t = d / ((sqrt(pow(v0, 2) + 2 * a * d) + v0) / 2)
 
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