Distance traveled in a circular motion

AI Thread Summary
A car accelerates around a curve with a radius of 31.7 m, maintaining a constant tangential acceleration of 2.97 m/s². The friction coefficient between the tires and the road is 0.851, which affects the car's ability to maintain its circular path. The initial calculation for the distance traveled before skidding was found to be 44.55 m, but this was deemed incorrect. The key issue identified is that the static friction must account for both the centripetal and tangential forces acting on the car. Properly incorporating these forces is essential for determining the correct distance before skidding occurs.
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Homework Statement



A car starts from rest and accelerates around a flat curve of radius R = 31.7 m. The tangential component of the car’s acceleration remains constant at at = 2.97 m/s2, while the centripetal acceleration increases to keep the car on the curve as long as possible. The coefficient of friction between the tires and the road is μk = 0.851. What distance does the car travel around the curve before it begins to skid? (Be sure to include both the tangential and centripetal components of the acceleration.)


Homework Equations



F=(mv^2)/r
F=ma
F=μN


The Attempt at a Solution


mv^2/r=μN
mv^2/r=μmg
μg=v^2/r
v^2=rμg
v^2=v(initial)^2+2ax
rμg=2ax
x=rμg/(2a)
x=(31.7)(.851)(9.81)/(2(9.81))
x=44.55m
This is how i attempted the problem, but am apparently incorrect. What am i doing wrong?
 
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The static friction that acts at the tyres has to cover the total accelerating force which includes both centripetal and tangential acceleration.

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