- #1

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My attempt:

I know each owner will travel a distance of 5m at 1.3m/s which equals 6.5s of time. The dog travels 3.0m/s for the 6.5s= 19.5m traveled, but the answer given is 11m. What am I doing wrong?

- Thread starter destinc
- Start date

- #1

- 17

- 0

My attempt:

I know each owner will travel a distance of 5m at 1.3m/s which equals 6.5s of time. The dog travels 3.0m/s for the 6.5s= 19.5m traveled, but the answer given is 11m. What am I doing wrong?

- #2

- 644

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How far do you travel in 6.5 sec if you go at 1.3 m/sec?I know each owner will travel a distance of 5m at 1.3m/s which equals 6.5s of time.

- #3

- 19

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Hey physics problems can be tough to get thru sometimes.

My attempt:

I know each owner will travel a distance of 5m at 1.3m/s which equals 6.5s of time. The dog travels 3.0m/s for the 6.5s= 19.5m traveled, but the answer given is 11m. What am I doing wrong?

You can use an equation that relates velocity, time, and distance to get your answer.

Remember, Average velocity = Δx divided by Δt...where x is displacement and t is time. The trick here is also that you have two people moving at the same velocity closing a distance of 10m.

Once you have the time it takes for these two people to meet, solve for the Δx of the dog.

- #4

NascentOxygen

Staff Emeritus

Science Advisor

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....My attempt:

I know each owner will travel a distance of 5m at 1.3m/s which equals 6.5s of time.✗

- #5

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You can also simplify the problem by treating one owner as being stationary and the other moving at 2.6m/s

EDIT: I got 11.5385, which I think you should round up...not quite sure about this method

EDIT: I got 11.5385, which I think you should round up...not quite sure about this method

Last edited:

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