Distance travelled of block, friction, forces

AI Thread Summary
A block with a mass of 1kg and a coefficient of static friction of 0.5 experiences a 7N force, resulting in a net force of 2.1N after accounting for static friction. The discussion highlights the need to calculate the kinetic frictional force, which is essential for determining the block's deceleration once it starts moving. Participants emphasize the importance of clarifying the problem, particularly regarding the duration of the applied force and the initial velocity. The kinematic equations are suggested as tools to find the distance traveled until the block comes to a stop. Without additional information, the block could theoretically travel indefinitely.
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Homework Statement


A block of mass 1kg has a coefficient of static friction of .5. If a 7N force is applied to the block what distance can the block travel? Coefficient of kinetic friction is .3


Homework Equations


F=ma


The Attempt at a Solution


I found the static frictional force to be (.5)(9.8)(1)=4.9N so the Fnet of the initial force applied is 2.1N. However I do not know how to find the distance the block traveled from there? Anybody know how to do this?
 
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You know the Coefficient of kinetic friction.Thats what you need here.
 
adjacent said:
You know the Coefficient of kinetic friction.Thats what you need here.

I know that I need to use kinetic friction but I don't how to use it with what I am giving. I think I might need to find velocity but how could I find that?
 
(you may redefine the question with "If a 7N force is applied to the block what distance can the block travel?,Until coming to a stop.
I think your question needs to be a bit clear.
 
Last edited:
adjacent said:
Find the kinetic frictional force and using F=ma,find the deceleration of the block when it is initially traveling with a constant force.(you may redefine the question with "If a 7N force is applied to the block what distance can the block travel?,Until coming to a stop.

Note:you may also need the kinematics equations
V=u+at
s=1/2(u+a)t2
s=ut+1/2at
v2=u2+2as

Using V^2=u^2+2as, I know that V will be 0, a will be 2.94 and s is the distance which am trying to find, I just don't know how to find u.
 
Make your question clear.A Force of 7N is applied for how many seconds?If we keep applying it forever,it won't stop moving at all.
 
As adjacent implies (now) the question makes no sense as it stands. In the absence of further information, there is no limit on how far it can travel.
 
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