# Distributing a Negative Sign

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## Homework Statement

$\sqrt{-3y-8}$ = $-\sqrt{y+4}+2$

I need to square both sides in order to solve for Y.
But, how do I distribute the negative sign on the right side? Would it be similar to (-x+2)2 or -(x+2)2?

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vela
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If it's less confusing for you, you could write the righthand side as $2-\sqrt{y+4}$.

1 person
Staff Emeritus
If it's less confusing for you, you could write the righthand side as $2-\sqrt{y+4}$.
To answer the question asked, squaring $-\sqrt{y+ 4}+ 2$ is $(-\sqrt{y+ 4}+ 2)^2= y+ 4- 4\sqrt{y+ 4}+ 4$.