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Distributing a Negative Sign

  1. Sep 20, 2013 #1

    Drakkith

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    1. The problem statement, all variables and given/known data

    [itex]\sqrt{-3y-8}[/itex] = [itex]-\sqrt{y+4}+2[/itex]

    I need to square both sides in order to solve for Y.
    But, how do I distribute the negative sign on the right side? Would it be similar to (-x+2)2 or -(x+2)2?
     
    Last edited: Sep 20, 2013
  2. jcsd
  3. Sep 20, 2013 #2

    vela

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    If it's less confusing for you, you could write the righthand side as ##2-\sqrt{y+4}##.
     
  4. Sep 20, 2013 #3

    Drakkith

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    Oh, well that makes perfect sense now. Thanks!
     
  5. Sep 21, 2013 #4

    HallsofIvy

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    To answer the question asked, squaring [itex]-\sqrt{y+ 4}+ 2[/itex] is [itex](-\sqrt{y+ 4}+ 2)^2= y+ 4- 4\sqrt{y+ 4}+ 4[/itex].
     
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