# Distributing a Negative Sign

1. Sep 20, 2013

### Drakkith

Staff Emeritus
1. The problem statement, all variables and given/known data

$\sqrt{-3y-8}$ = $-\sqrt{y+4}+2$

I need to square both sides in order to solve for Y.
But, how do I distribute the negative sign on the right side? Would it be similar to (-x+2)2 or -(x+2)2?

Last edited: Sep 20, 2013
2. Sep 20, 2013

### vela

Staff Emeritus
If it's less confusing for you, you could write the righthand side as $2-\sqrt{y+4}$.

3. Sep 20, 2013

### Drakkith

Staff Emeritus
Oh, well that makes perfect sense now. Thanks!

4. Sep 21, 2013

### HallsofIvy

To answer the question asked, squaring $-\sqrt{y+ 4}+ 2$ is $(-\sqrt{y+ 4}+ 2)^2= y+ 4- 4\sqrt{y+ 4}+ 4$.