What is the covariance matrix (X,Y) for the joint distribution of X and Y?

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The discussion focuses on determining the covariance matrix for the joint distribution of two random variables, X and Y, where X represents the number of clubs in a 13-card hand and Y represents the number of queens in the same hand. The probability density function for X is provided, along with the joint distribution of X and Y. The expected value of Y, E[Y], is calculated using a summation involving combinations. The covariance between X and Y is defined using the formula Cov(X,Y) = E[XY] - E[X]E[Y], with further details on how to compute the covariance matrix. The conversation emphasizes the need to calculate E[XY] and the variances to complete the covariance matrix.
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X = # of clubs in a 13 card hand drawn at random without replacement from 52 card deck
Y= # of queens in the same 13 card hand

the pdf of x is f_x (x) = (13 choose x)( 39 choose 13-x) / (52 choose 13) for x=< x =< 13
and o otherwise

the joint distribution of x and y = (13 choose x) ( 5 choose y) ( 34 choose 13-x-y)/ (52 choose 13) for 0 =<x =<13 0 =< y =< 4 0<=x+y<=13 and 0 otherwise

What is E(Y) and what is the covariance matrix (X,Y)?

E[Y] = Sum y=1 to 4 of y* (4 choose y)(48 choose 13-y)/ (52 choose 13) ?

I have no idea on the matrix.
 
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Hey nikki92.

The covariance of two random variables is given by Cov(X,Y) = E[XY] - E[X]E[Y] where E[XY] = Summation (over x) Summation over y P(X=x,Y=y)*xy (Or an integral for continuous random variable).

The covariance matrix has Cov(Xi,Xj) at the (i,j) position in the matrix and note that Cov(Xi,Xi) = E[Xi^2] - {E[Xi]}^2 = Var[Xi] so you will have four entries with Var[X1], Var[X2] in (1,1) (2,2) and Cov(X,Y) in the other positions.
 
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