Divergence of a rank-2 tensor in Einstein summation

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SUMMARY

The divergence of a rank-2 tensor, represented as a matrix, is calculated by applying the divergence operator to each column. The correct expression in Einstein summation notation is given by \partial_i M_{ij}, where i represents the summation index for the rows and j distinguishes the columns. This formulation ensures that each entry of the tensor is summed appropriately over the index i.

PREREQUISITES
  • Understanding of rank-2 tensors and their representation as matrices
  • Familiarity with the divergence operator in vector calculus
  • Knowledge of Einstein summation convention
  • Basic concepts of tensor calculus
NEXT STEPS
  • Study the application of the divergence operator on higher-order tensors
  • Learn about the implications of the Einstein summation convention in tensor calculus
  • Explore examples of tensor operations in general relativity
  • Investigate the relationship between tensor divergence and physical quantities in physics
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Students and professionals in physics, particularly those studying general relativity, as well as mathematicians and engineers working with tensor calculus and vector fields.

Niles
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Homework Statement


Hi

When I want to take the divergence of a rank-2 tensor (matrix), then I have to apply the divergence operator to each column. In other words, I get
<br /> \nabla \cdot M = (d_x M_{xx} + d_y M_{yx} + d_zM_{zx}\,\, ,\,\, d_x M_{xy} + d_y M_{yy} + d_zM_{zy}\,\,,\,\, d_x M_{xz} + d_y M_{yz} + d_zM_{zz})<br />
How would I write this vector in Einstein summation? Is it correct that it would be
<br /> \partial_i M_{ij}<br />
 
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Niles said:

Homework Statement


Hi

When I want to take the divergence of a rank-2 tensor (matrix), then I have to apply the divergence operator to each column. In other words, I get
<br /> \nabla \cdot M = (d_x M_{xx} + d_y M_{yx} + d_zM_{zx}\,\, ,\,\, d_x M_{xy} + d_y M_{yy} + d_zM_{zy}\,\,,\,\, d_x M_{xz} + d_y M_{yz} + d_zM_{zz})<br />
How would I write this vector in Einstein summation? Is it correct that it would be
<br /> \partial_i M_{ij}<br />

IIRC, yes.

You have three entries, that distinguished by a new j value, since it appears once, and each entry is a summation over i, since it appears twice.
 

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