Division as Subtraction: A New Perspective

chimath35
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So, I assume to look at multiplication as addition; how should I look at division?
 
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chimath35 said:
So, I assume to look at multiplication as addition; how should I look at division?

And why would you do that? Do you have some context for your question?
 
I am just saying you can break down multiplication into a*b=a+a+a...
 
chimath35 said:
I am just saying you can break down multiplication into a*b=a+a+a...

Then you think of division using the same idea. If c=a*b means c=(a+a+a+... b times) then c/a=b also means c=(a+a+a+... b times).
 
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Dick said:
Then you think of division using the same idea. If c=a*b means c=(a+a+a+... b times) then c/a=b also means c=(a+a+a+... b times).

I got on trouble for this post; I really thought that what I asked was legitimate. Those three concrete requirements for posting homework help don't really seem feasible all the time. Maybe they thought it was too vague, but I honestly needed help with that.
 
chimath35 said:
I got on trouble for this post; I really thought that what I asked was legitimate. Those three concrete requirements for posting homework help don't really seem feasible all the time.
Nevertheless, those are the rules.
chimath35 said:
Maybe they thought it was too vague, but I honestly needed help with that.
Your question was too vague, which is why Dick asked what the context was for your question. We aren't mindreaders here. When you post a problem on this site, put some effort into presenting the problem unambiguously, and show us that you have at least tried to come up with a solution.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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