Do Factoring and Simplification Affect the Domain of a Function?

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Factoring and simplification do not affect the domain of a function; the domain should be determined based on the original function. For the functions f(x) = (x^2)/x and g(x) = x, f is not defined at x = 0, giving it a domain of ℝ-{0}, while g is defined for all real numbers, with a domain of ℝ. Although f(x) and g(x) are equivalent for all nonzero x, they are not the same function due to their differing domains. It is essential to find the domain based on the original function before any simplification. Ultimately, the domain should be assessed before and after simplification to ensure accuracy.
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Suppose I have a function f defined on x, f(x) = (x^2)/x and another function g defined on x, g(x) = x. Are both these functions the same?

I mean, when you try to determine the Domain of a function, do you simplify it as much as possible, and then find the Domain? Or find the Domain on the face of the function?

In this case, what I think is that f has Domain-->ℝ-{0}, while g has Domain--> ℝ. Is this correct?
 
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No, they are not the same. Indeed, f is not defined in 0, while g is.

However, f(x) and g(x) are the same for all nonzero x.
 
But of course, you can simplify without altering domains.

f(x) = g(x), ~ \forall x, ~ \mbox{if} ~ f(x)=1 ~ \mbox{and} ~ g(x) = \frac{x^2 +1}{x^2 +1}

Bottom line, find the domain and see if it changes by any possible factoring/simplification.
 
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