Do I use a system of equations for this projectile motion?

AI Thread Summary
To solve the projectile motion problem of a basketball kicked by Chuck Norris, it's essential to break down the motion into horizontal and vertical components using the equations of motion. The initial velocities can be determined using Vox = v0cos(39) and Voy = v0sin(39). Separate equations for horizontal and vertical motion must be established to find the initial velocity (v0) and the time taken for the ball to reach the hoop. The horizontal distance and height equations can be combined to solve for v0 and time. Understanding the correct application of sine and cosine functions is crucial, as tangent does not replace them in this context.
phantomcow2
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1. Chuck Norris kicks a basketball from the ground into a basketball hoop, it makes it in perfectly. THe hoop is 150m away, and 6m above the ground. He kicks the ball at a 39 degree angle. How long does it take for the ball to reach the net? What was the initial velocity?



2. X1=X0+v0t+1/2at^2



3. So breaking it down, I know that Vox = v0cos(39)
And that voy= v0Sin(39

Doesn't that mean I use the tangent function? Can somebody jumpstart my memory? :frown:
 
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A little background:
As a homework assignment, we were told to make up a moderate problem and share with the class as a review for upcoming midterms. I solved one of these a few months ago and cannot remember at all how.
 
Your components of velocity are correct. Try writing your equation out twice; once for vertical and once for horizontal motion.
 
phantomcow2 said:
2. X1=X0+v0t+1/2at^2
That's a good generic equation. Hint: Write separate equations for the horizontal and vertical motions. (How do they differ?)

3. So breaking it down, I know that Vox = v0cos(39)
And that voy= v0Sin(39

This is good. Combine this with the above equations and you'll be able to solve for V0.
 
Once you write the equation for the horizontal motion, try to solve it to get v_0t and substitute it in the equation for verticle motion. This will give you time! Try it!
 
So
150=0+v0Sin(39) + 1/2*0*t^2
6=0+v0Cos(39) + 1/2*-9.81t^2

From here, doesn't tangent end up replacing Sin and Cosine though?
 
phantomcow2 said:
So
150=0+v0Sin(39) + 1/2*0*t^2
6=0+v0Cos(39) + 1/2*-9.81t^2
You've mixed up your sines and cosines.

From here, doesn't tangent end up replacing Sin and Cosine though?
No. You know the sine and cosine, so they are just numbers. Combine the two equations and solve for v0.
 
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