Exploring the Decay of Photons: Insights from Experts"

In summary: Yes... and why bother checking it? No one will ever witness the decay of a photon no matter how long they wait since they travel at the speed of light in all reference frames, and hence time dilation in essence
  • #1
brianthewhitie7
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[Mentor's note: this post was moved from a thread about gravitons where it was off topic.]

I know this kind of off topic but do photons decay?
 
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  • #2
No...
 
  • #3
brianthewhitie7 said:
[Mentor's note: this post was moved from a thread about gravitons where it was off topic.]

I know this kind of off topic but do photons decay?

Even if they were unstable, they are traveling at the speed of light and therefore, by the very nature of time dilation in Special Relativity, they cannot decay in any reference frame.
 
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  • #4
Well, in so much as there is a valid Feynman diagram for virtual photons:
p--> e+, e- -->p
(a virtual photon spends some of its time as an electron/positron pair)
I suppose you could think of that as a "decay".
 
  • #5
[tex]\gamma^*\rightarrow e^+e^-[/tex] should not be considered as "photon decay". At most you can name it "virtual photon transition". When you say something "decays", one would immeditely associate the context of "half-lives" (decay rate) in radioactive decays of nuclear physics, or in particle physics "mean half life" (or width). Those refer to real particles, whose mass are well defined. I do not think anybody would talk about the decay of a virtual particle, which would be rather odd.
 
  • #6
humanino said:
[tex]\gamma^*\rightarrow e^+e^-[/tex] should not be considered as "photon decay". At most you can name it "virtual photon transition". When you say something "decays", one would immeditely associate the context of "half-lives" (decay rate) in radioactive decays of nuclear physics, or in particle physics "mean half life" (or width). Those refer to real particles, whose mass are well defined. I do not think anybody would talk about the decay of a virtual particle, which would be rather odd.
Totally agreed.
BTW: While we're on the topic of virtual particle transitions, would you care to speculate on possible G --> ? -->G transitions, where G is a Graviton.
 
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  • #7
abbottsys said:
Totally agreed.
BTW: While we're on the topic of virtual particle transitions, would you care to speculate on possible G --> ? -->G transitions, where G is a Graviton.
In graviton theories, G interacts with matter, so any pair could appear in a Feynman diagram.
 
  • #8
humanino said:
[tex]\gamma^*\rightarrow e^+e^-[/tex]

The translation-invariance of the vacuum means that momentum conservation disallows this transition - at least at the tree-level - since the three-momentum of the virtual pair must be zero while that of a photon is always nonvanishing.
 
  • #9
josh1 said:
the three-momentum of the virtual pair must be zero
what ? :confused:
this transition is actually observed, and I think tree-level or loop(s) diagrams have nothing to do with globally conserved current such as momentum (for real/fully calculated processes)
 
  • #10
humanino said:
what ? :confused:
this transition is actually observed, and I think tree-level or loop(s) diagrams have nothing to do with globally conserved current such as momentum (for real/fully calculated processes)

At tree-level we can have two-photon annihilation of an electron and positron. But one photon cannot convert directly into a virtual pair.
 
  • #11
josh1 said:
But one photon cannot convert directly into a virtual pair.
The star on my photon indicated he is the virtual guy. The pair is real.

Do you agree that, tree-level or loops, three-momentum conservation is respected anyway ?

Do you agree that a virtual photon has a finite mass, and thus a rest frame ?

I think you do.
 
  • #12
humanino said:
The star on my photon indicated he is the virtual guy. The pair is real.

That explains it. Sorry for wasting your time.
 
  • #13
humanino said:
Do you agree that a virtual photon has a finite mass, and thus a rest frame ?
A virtual photon is virtual (as in not real) and has E^2-p^2<0.
Try to find a rest frame for that.
 
  • #14
Meir Achuz said:
A virtual photon is virtual (as in not real) and has E^2-p^2<0.
There are virtual photons in the time-like region as well. That's what I had in mind, and I admit that I have been sloppy. Typically, vitual photons produced in [tex]e^+e^-[/tex] annihilation are in the timelike region, whereas virtual photons produced in lepton scattering are in the spacelike region.
 
  • #15
In the Manchester series Particle physics textbook it mentions that it has been asserted controvercialy by some that the lifetime of a photon is ~10^31 years

I haven't got it with me, i'll check later
 
  • #16
neu said:
Manchester series Particle physics textbook
The authority reference in the community is the Review of particle physics, which is freely available on the web...
They do not seem to me to report on any "photon decay" experiment however.
Maybe because nobody is even checking it :biggrin:

No seriously, photon do not decay...
 
  • #17
humanino said:
The authority reference in the community is the Review of particle physics, which is freely available on the web...
They do not seem to me to report on any "photon decay" experiment however.
Maybe because nobody is even checking it :biggrin:

No seriously, photon do not decay...

Yes... and why bother checking it? No one will ever witness the decay of a photon no matter how long they wait since they travel at the speed of light in all reference frames, and hence time dilation in essence dooms the photon to immortality. The very concept of searching for photon decay is inherently flawed.
 
  • #18
neu said:
In the Manchester series Particle physics textbook it mentions that it has been asserted controvercialy by some that the lifetime of a photon is ~10^31 years

I haven't got it with me, i'll check later

Haha, i checked and they were actualy talking about protons. Still that's mental, protons are unstable?
 
  • #19
neu said:
Haha, i checked and they were actualy talking about protons. Still that's mental, protons are unstable?
Well, the proton stability is much more surprising than that of the photon ! In Grand Unified Theories, particulary SU(5) scheme, it is predicted that the proton must decay. Someone said, I don't remember who, but "I would feel it in my bones" :smile:

Anyway, so far the proton does not seem to decay, but contrary to the photon, there are good reasons to check it.
 
  • #20
Protons actually are predicted to decay in the standard model as well via dimension 6 operators.
 
  • #21
Haelfix said:
Protons actually are predicted to decay in the standard model as well via dimension 6 operators.
I never heard of that !
Hadronic number non-conservation within the standard model !?
Do you have any reference I could read, I would be quite interested :confused:

edit

I found it :
Symmetry Breaking through Bell-Jackiw Anomalies
G. 't Hooft
Phys. Rev. Lett. 37, 8 - 11 (1976)
In models of fermions coupled to gauge fields certain current-conservation laws are violated by Bell-Jackiw anomalies. In perturbation theory the total charge corresponding to such currents seems to be still conserved, but here it is shown that nonperturbative effects can give rise to interactions that violate the charge conservation. One consequence is baryon and lepton number nonconservation in V-A gauge theories with charm. Another is the nonvanishing mass squared of the [tex]\eta[/tex].
Seems serious but kind of old. Thank you very much for pointing me to that :smile:
Please let me know if you have a more recent reference.
 
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  • #22
humanino said:
adronic number non-conservation within the standard model !?
Quite a number of attempts at explaining baryogenesis and leptogenesis in the early universe require a lack of conservation in that regard. Can't remember any references off the top of my head, but searching for 'leptogenesis' on ArXiv will bring up the relevant material I think.

Though if the operators are 6 dimensional, would it still be 'the Standard Model'? 6 dimensional operators are non-renormalisable so you'd have to put in a cut off to make it viable.
 
  • #23
Haelfix said:
Protons actually are predicted to decay in the standard model as well via dimension 6 operators.
"Standard Model" means different things to different people.
In my terminology, which I think is fairly "standard", GUT theories that require proton
decay are considered beyond the standard model, which is part of their allure.
 
  • #24
Meir Achuz said:
"Standard Model" means different things to different people.
In my terminology, which I think is fairly "standard", GUT theories that require proton
decay are considered beyond the standard model, which is part of their allure.

I think most people's definitions of the "Standard Model" would not include proton decay. Afterall, in order to conserve baryon number in the "Standard Model", the proton is naturally constrained to not decay because it is the lightest baryonic resonance...

Which brings up a further question... If physics beyond the Standard Model is capable of baryon number non-conservation, then wouldn't it be interesting if physics beyond the Supersymmetric Model would allow for R-parity violation? In that way, the lightest R-negative SUSY resonance would also be capable of decay, despite the fact that it would be constrained from decay in a SUSY model...

I'm not saying that I think that would be true, but its just a hypothetical thought...
 
  • #25
Hi Meir, I am not talking about GUT physics, but rather the standard model lagrangian.

Lepton and Baryon number conservation is an accidental symmetry of the perturbative 'renormalizable' standard model lagrangian. Weinberg, Wilcek and others showed years ago that this is broken by dimension 6 operators (suppressed by M^2, where M is some heavy mass scale). If you take the point of view of the standard model as an effective theory, then there is nothing that prevents these terms from being realized.

Also, T'Hooft and others pointed out that nonperturbative effects can also break baryon number conservation.

The problem with all these proposals is they typically output proton stability on the order of 10^94 years or something ridiculous like that. Eg the effects are so ridiculously small, we already expect something else to swamp them ipso facto.

For instance, from cosmology we have the Sakharov conditions to output the observed matter-antimatter asymmetry, which requires baryon number non conservation. There is absolutly no way these somewhat esoteric considerations could possibly lead to sufficient baryon nonconservation, ergo we know that some other physics must control the protons fate. Enter GUTs, and other proposals
 
  • #26
Haelfix said:
Hi Meir, I am not talking about GUT physics, but rather the standard model lagrangian.

Lepton and Baryon number conservation is an accidental symmetry of the perturbative 'renormalizable' standard model lagrangian. Weinberg, Wilcek and others showed years ago that this is broken by dimension 6 operators (suppressed by M^2, where M is some heavy mass scale). If you take the point of view of the standard model as an effective theory, then there is nothing that prevents these terms from being realized.

Also, T'Hooft and others pointed out that nonperturbative effects can also break baryon number conservation.

The problem with all these proposals is they typically output proton stability on the order of 10^94 years or something ridiculous like that. Eg the effects are so ridiculously small, we already expect something else to swamp them ipso facto.

For instance, from cosmology we have the Sakharov conditions to output the observed matter-antimatter asymmetry, which requires baryon number non conservation. There is absolutly no way these somewhat esoteric considerations could possibly lead to sufficient baryon nonconservation, ergo we know that some other physics must control the protons fate. Enter GUTs, and other proposals

I was not aware that the Standard Model included a baryon-number non-conserving term... this is very interesting, do you have a reference for this beyond the mentioned names above?
 
  • #27
mormonator_rm said:
do you have a reference for this beyond the mentioned names above?
Although I have given t'Hooft original reference, I would be glad to be pointed towards to a recent review. The original paper has to many quotations ! It would have taken me too long to go through them. But as Haelfix pointed out, the decay in this case is vanishing small, so maybe no recent paper has investigated the situation.
 

1. What is the decay of photons and why is it important to study?

The decay of photons is the process by which a photon, the fundamental unit of light, transforms into other particles or energy forms. It is important to study because it helps us understand the behavior of light and its interactions with matter, which has practical applications in fields such as optics, telecommunications, and energy production.

2. How do scientists study the decay of photons?

Scientists study the decay of photons using a variety of techniques, such as high-energy particle colliders, spectroscopy, and astrophysical observations. These methods allow us to observe the behavior of photons in different environments and energy levels, providing insights into their decay processes.

3. What have scientists learned from studying the decay of photons?

Through studying the decay of photons, scientists have gained a better understanding of the fundamental forces and particles that govern the universe. They have also been able to develop advanced technologies, such as medical imaging and solar cells, that rely on our understanding of photon behavior.

4. What are some current areas of research in the decay of photons?

Some current areas of research in the decay of photons include studying the properties of the Higgs boson, which is responsible for giving particles mass, and searching for new particles or forces that may be involved in photon decay. Scientists are also exploring the possibility of using photon decay as a way to detect dark matter, a mysterious substance that makes up a large portion of the universe.

5. How does the decay of photons relate to the theory of relativity?

The decay of photons is intimately connected to the theory of relativity, which describes the relationship between space, time, and gravity. According to Einstein's famous equation E=mc², mass and energy are equivalent, and photons have both energy and momentum. Therefore, the decay of photons involves the conversion of energy into mass and vice versa, which is a key concept in relativity.

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