I Do there exist surfaces whose boundary is a closed knot?

jk22
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I ask this for the condition of application of Stoke's theorem.
 
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Every knot is the boundary of an orientable (you want this for Stokes' theorem) surface. Look up "Seifert surface".
 
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Those slides mention that Lawson, in his dissertation (Annals of Mathematics, November 1970), proved that "all genera" can be realized as minimal surfaces in the 3-sphere.

In fact, Lawson shows that all compact orientable surfaces exist as embedded minimal surfaces in S3, and that all compact non-orientable surfaces but one can occur as immersed minimal surfaces in S3. The exception is the projective plane, which Lawson proves cannot occur as a minimal immersed surface in S3.
 
A sphere as topological manifold can be defined by gluing together the boundary of two disk. Basically one starts assigning each disk the subspace topology from ##\mathbb R^2## and then taking the quotient topology obtained by gluing their boundaries. Starting from the above definition of 2-sphere as topological manifold, shows that it is homeomorphic to the "embedded" sphere understood as subset of ##\mathbb R^3## in the subspace topology.
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