Do you know what this particular unitary operator is?

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Recall that the unitary operator exp(\frac{i}{\hbar}aX) transform the operator P_x +a to P_x.

Now, what is the unitary operator that transform the operator P_x +aX to P_x ??

:confused:
 
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QMrocks said:
Recall that the unitary operator exp(\frac{i}{\hbar}aX) transform the operator P_x +a to P_x.

Now, what is the unitary operator that transform the operator P_x +aX to P_x ??

:confused:

you mean P_x to P_x + a

exp(- \frac{i}{\hbar}aX)

: )

Seratend.

EDIT: sorry bad reading:
exp( \frac{i}{\hbar}aX^2/2) is the answer to your question
 
Last edited:
seratend said:
exp(- \frac{i}{\hbar}aX)

: )

Seratend.

Nope......
 
There is no typo.
 
QMrocks said:
There is no typo.

See corrected previous post.

Seratend.
 
seratend said:
EDIT: sorry bad reading:
exp( \frac{i}{\hbar}aX^2/2) is the answer to your question

Thanks. Thats the answer i tempted to throw in too. But i have my doubts.. :confused:
 
QMrocks said:
Thanks. Thats the answer i tempted to throw in too. But i have my doubts.. :confused:

Doubts, why? You just have to calculate.
Hint: try to see what the unitary operator exp(i a(X)) does on the momentum operator.

Seratend.
 
My bad, Seratend. You are absolutely right! Case close :)
 

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