Does a resistor affect the electric field in a circuit?

AI Thread Summary
A potential difference creates an electric field, which exists between the leads of a power supply even when disconnected. Connecting the leads to a resistor does not eliminate the electric field outside the resistor; it simply allows current to flow within the resistor. The electric field is present both inside and outside the resistor, with the current being the movement of charge within the resistor. The behavior of the electric field in this scenario is complex and not limited to the resistor itself. Understanding these dynamics is crucial for analyzing circuit behavior.
Chengjun Li
Messages
4
Reaction score
0
We all know that wherever there is potential difference in space, there will be electric field there. So if we set a power supply to output 1V, but we connect the two leads to nothing, just leave them in air, the ends of the two leads have a potential difference of 1V, there will be a electric field produced between the two ends. My question is if we connect the two leads to a resistor, will the electric field be different from without a resistor?Will the electric field in this case only exists inside the resistor?
 
Physics news on Phys.org
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top