Does a rigid rod store any energy?

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SUMMARY

A rigid rod can be modeled as a spring with a spring constant k and compression x, where the potential energy is defined by the formula E = 1/2 kx². When the rod is in equilibrium with an applied force F, the relationship F = kx holds true, leading to an alternative expression for potential energy as E = 1/2 (F²/k). As the spring constant k approaches infinity, the energy stored in the spring approaches zero for any applied force, confirming that a very stiff spring does not store energy effectively.

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jcap
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I presume that a rod can be modeled as a spring with spring constant k and compression x.

The potential energy in a spring is given by:
[tex] E = \frac{1}{2}kx^2[/tex]
If the spring is in equilibrium with an applied force F then we have:
[tex] F = k x[/tex]
Thus the potential energy in the spring in terms of the force is:
[tex] E = \frac{1}{2}\frac{F^2}{k}[/tex]
Thus if we have a very stiff spring so that [itex]k\rightarrow\infty[/itex] then the energy stored in the spring tends to zero for any force applied to the spring.

Is that correct?
 
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You answered your own question.

Chet
 
Perhaps confirm it by looking at the work done by the applied force as it compresses the spring?

work = force * displacement

If the spring is very stiff the displacement is going to approach zero.
 

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