Does a symmetry need to leave the whole action invariant?

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    Invariant Symmetry
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SUMMARY

This discussion centers on the relationship between symmetry and action invariance in classical physics. It asserts that while traditional definitions of symmetry require invariance of the action, a more practical approach is to consider symmetries that map physical solutions to physical solutions, even if they do not preserve the action for unphysical solutions. The necessity of action invariance is linked to Noether's theorem, which connects symmetries to conservation laws, thereby justifying the requirement for invariance in the context of physical theories.

PREREQUISITES
  • Understanding of classical mechanics and action principles
  • Familiarity with Noether's theorem and its implications
  • Knowledge of extremal solutions in variational calculus
  • Basic concepts of symmetry in physical theories
NEXT STEPS
  • Explore the implications of Noether's theorem in various physical systems
  • Study variational calculus and its applications in classical mechanics
  • Investigate different types of symmetries and their classifications
  • Examine case studies where action invariance is not strictly necessary
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This discussion is beneficial for physicists, particularly those studying classical mechanics, theoretical physicists interested in symmetries and conservation laws, and students of advanced physics looking to deepen their understanding of Noether's theorem.

nonequilibrium
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Typically a symmetry is taken to be something that leaves the action invariant. However, on a classical level, isn't that asking way too much? To match what we conceptually mean by symmetry, we only need something that maps solutions to solutions, so something which leaves the action invariant in the neighbourhood of extremal solutions(?) (After all who cares what a symmetry operation does to unphysical solutions?). Is it because of Noether's theorem?
 
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Alright I solved my own problem. You need it to get Noether's theorem to work.
 

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