Drakkith
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256bits said:Torque is not a function of the difference in radial velocity between the slipping clutch and mating pressure plates. The torque will not change to the driven shaft if the clutch is slipping whether or not the engine speeds up, as the friction within the clutch would be independant of the difference in velocity. Power on the other hand does depend on the radial velocity. With a slipping clutch, the excess power that is not transmitted to the driven shaft from the engine will end up as heat within the clutch and mating parts.
I don't follow you.
sophiecentaur said:I think that there is not just a simple answer to this but I think you really have to consider Power as well as torque.
I think it is very simple. If you are not at max torque, then allowing the clutch to slip and the engine to rev up to get to max torque CAN produce more torque to the wheels through the drivetrain.
Clearly, a IC engine can't go slower than about 1.5k with any appreciable power output. You can get around this, at takeoff, by revving the engine and slipping the clutch (wasting power but producing more torque into the gearbox).
This is exactly the phenomenon this thread is about.
This will work in first gear and even, if you're being sloppy, in second. If you are in third, by mistake, then it's very hard and you can only accelerate (pull away) along the flat. As you go up through the gears, you need more torque at the input to the gearbox for a given amount of acceleration (torque at the wheels) - at a given speed - so the engine needs to be revving faster and the clutch needs to be dissipating progressively more power.
Gears are irrelevant to the discussion. This is solely about torque input to the clutch. The amount of torque applied will change depending on how much the clutch is slipping and how much torque the engine is providing.