Does Constant Acceleration Always Change Velocity's Magnitude?

AI Thread Summary
Constant acceleration does not always change the magnitude of velocity, as demonstrated by objects in steady circular orbits. In such cases, while the direction of the velocity vector changes due to centripetal acceleration, its magnitude remains constant. The discussion highlights that velocity is a vector defined by both magnitude and direction, meaning that a change in direction can occur without a change in magnitude. A counterexample is provided where acceleration is zero and velocity is constant, further illustrating that not all forms of acceleration lead to changes in velocity's magnitude. Ultimately, the key takeaway is that velocity can change direction while maintaining a constant magnitude under specific conditions.
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The magnitude of the velocity of an object must change if the magnitude of its acceleration is a constant. True or false?

I chose true, however the correct answer is false. Here's my reasoning: If acceleration is constant, that means velocity is linear. If velocity is linear, that means it's magnitude is increasing.

Where did I go wrong here?
 
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consider the velocity and acceleration of an object in a steady circular orbit for a counterexample to your reasoning.
 
What if the velocity is constant?
 
Then acceleration is zero
 
The acceleration also has a constant of zero.
 
velocity is a vector and it is defined by it's magnitude and direction-should any of these change, we say that velocity changes. When you have a non zero acceleration,velocity will surely change, but since it is a vector it doesn't have to be it's magnitude that changes. circular orbit is indeed a very good example.
 
Well if its not its magnitude, then what changes? Direction?
 
To take the example of a steady circular orbit (e.g. Earth around the Sun) - the Earth is held in the orbit by acceleration that is directed towards the Sun but has a constant amplitude. The velocity vector changes but again its amplitude is constant.

Since you only have to provide one counterexample to disprove the original statement, another answer would be a=0, v=const, but only because of a little slop in the problem formulation IMHO :-)
 
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