Does f(x) Approach Zero as x Approaches Infinity?

  • Thread starter Thread starter Math_Frank
  • Start date Start date
  • Tags Tags
    Integral
Math_Frank
Messages
27
Reaction score
0

Homework Statement



Given the odd integral

\int_{a}^{b} f(x) dx How do I prove that

f(x) -> 0 for x \to \infty??

The Attempt at a Solution



Is it? For the above to be true, then there exist an \epsilon > 0 such that

|\int_{a}^{b} f(x) dx-0| \leq \epsilon?

I am stuck here!

Am I going the right way?

Sincerely
Frank
 
Physics news on Phys.org
What you've written doesn't really make sense. What is this question from and about?
 
NateTG said:
What you've written doesn't really make sense. What is this question from and about?

The Question is

Given the integeral

f(t) = \int_{t}^{2t} e^{-x^2} dx then prove that if f(x) \to 0 then

n \to \infty

Isn't that convergens or it simply existence of the limit?
 
Math_Frank said:
The Question is

Given the integeral

f(t) = \int_{t}^{2t} e^{-x^2} dx then prove that if f(x) \to 0 then

n \to \infty

Isn't that convergens or it simply existence of the limit?

Where does n come from?

Do you mean "\lim_{x \rightarrow \infty} f(x)=0" when you write "f(x) \to 0"
 
NateTG said:
Where does n come from?

Do you mean "\lim_{x \rightarrow \infty} f(x)=0" when you write "f(x) \to 0"

Yes.
 
You need to show both existence and convergence of the limit.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top