Does Isothermal Heat Flow Out Contradict the Second Law of Thermodynamics?

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Homework Statement



When there is a heat flow out of the system during a reversible isothermal processthe entropy of the system decreases.Why does this not violate the 2nd law of thermodynamics?

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The Attempt at a Solution

I hope this is correct.Please check and confirm.


Because the question uses the word "system" quite loosely. They are using "system" to mean the gas or other working substance from which the heat flows. But in terms of the second law, the word "system" refers to everything that loses or gains heat during the process.

So while the gas releases heat and the entropy of the gas decreases, the heat is absorbed by the environment (which must be included in the "system") and the entropy of the environment increases. Overall the total change in entropy is positive, as the increase for the environment is greater than the decrease for the gas.
 
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when there is a decrease in this enrophy, the entropy of the surroundings increases, u are quite right. system in the law refers to everything
 
OK thank you.
 
In fact, if it's reversable, then the entropy increase of the surroundings exactly matches the entropy decrease of the system.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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